4x^2=73

Solution for 4x^2=73 equation:

4x^2=73

We move all terms to the left:

4x^2-(73)=0

a = 4; b = 0; c = -73;
Δ = b2-4ac
Δ = 02-4·4·(-73)
Δ = 1168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1168}=\sqrt{16*73}=\sqrt{16}*\sqrt{73}=4\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{73}}{2*4}=\frac{0-4\sqrt{73}}{8}
=-\frac{4\sqrt{73}}{8}
=-\frac{\sqrt{73}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{73}}{2*4}=\frac{0+4\sqrt{73}}{8}
=\frac{4\sqrt{73}}{8}
=\frac{\sqrt{73}}{2}
$